Any template tag to show parent menu title as sub menu title

[sunjoomoon]

In the side bar to show sub menu title, is there such template tag? Ex, Product > Software > Mobile and I am in Mobile page, then sub menu title is the root of selected menu which n this case is Product.

[batiste]

It is a bit hard to understand what you mean but I think this should satisfy your needs:

http://django-page-cms.readthedocs.org/en/latest/navigation-template-tags.html#pages-dynamic-tree-menu

[batiste]

Here is the template that you can replicate within your project to fit your needs. Tell me if this template tag didn't fit your needs somehow: https://github.com/batiste/django-page-cms/blob/master/pages/templates/pages/dynamic_tree_menu.html

[sunjoomoon]

Thanks for the notes, I tried all available in the document but not being able to achieve my needs.

For example, from below page menus and I am in the Mobile page, then I wish to show the top most page title. In this case Product is the top most page, so a template to show product.title. So this can be shown in all the pages under Product pages.

Product
- Software 
- - Mobile

[batiste]

If I understand your you have this tree::

Product
- Software 
- - Mobile

And you want to only display:

Product

?

[sunjoomoon]

Yes. For all the pages under Product, the 5ah to show Product. Same as page title which differs for every page but sidemenu title always shows the top most menu title for all the pages under Product page. Hope this clears up the confusion.

[batiste]

Edited: wrong example

Well Django Page CMS uses Django MPTT to represent trees. You can use get_root to get the root page ("the product page"): http://django-mptt.github.io/django-mptt/mptt.models.html#mptt.models.MPTTModel.get_root

So I guess things would look a bit like this

{{ current_page.get_root.title }}

Or use pages_navigation which contains all the root pages

{% for page in pages_navigation %}
     {% if page == current_page.get_root %}
          Do something specific with the root page
     {% endif %}
{% endfor %}

[sunjoomoon]

Hmm, did not think of that before hand, let me give it a try. Your advice makes good sense. Thanks.

[sunjoomoon]

Trying things out as per your advice, here is what I did. I put tags in the head of the template

{% load cache pages_tags ckeditor_placeholder mptt_tags %}

And put the code like below (perhaps something is missing here, I am afraid)

<h3 class="widget-title"> {% current_page.get_root().title() %} </h3>

Then below returned, what am I missing?

Invalid block tag: 'current_page.get_root().title()', expected 'endblock'

Traceback detail shows

/../pages/views.py in __call__
                answer = self.delegate(request, context, delegation, **kwargs)
                if answer:
                    return answer
            if kwargs.get('only_context', False):
                return context
            template_name = kwargs.get('template_name', template_name)
                        return render(request, template_name, context)  ...

        def resolve_page(self, request, context, is_staff):
            """Return the appropriate page according to the path."""
            path = context['path']
            lang = context['lang']
            page = Page.objects.from_path(path, lang,

[batiste]

You don't put parenthesis in the django template language (I know this is weird sometimes). Also you need {{ }} for an expression ({% %} is for template tags) so that will that:

{{ current_page.get_root.title }}

Or better yet, using the show_content template tag (this one handle translation depending of the user language):

{% show_content current_page.get_root title %}

[sunjoomoon]

Many thanks. Yes, they worked well - just a little typo got me stranded for a minute though.

This worked well
{{ current_page.get_root.title }}

Below first showed none
{% show_content current_page.get_root title %}

So I had a look around existing templatetags, and found out a typo - missed string " ". And below worked well.
{% show_content current_page.get_root "title" %}