The expression of "1 == 2 ? Random.Range(0, 1) : 3" results in a parser exception

[zzxiang]

The expression is:

1 == 2 ? Random.Range(0, 1) : 3

The following exception is reported:

ExpressionParserException: A colon ':' symbol is expected in conditional '?' expression.

Changing Random.Range(0, 1) to Random.value makes the exception disappear.

However, 1 == 2 ? 3 : Random.Range(0, 1) can be correctly parsed.

[deniszykov]

Hi! Thanks for report. I will look what is wrong with parser.

[deniszykov]

I have fixed this issue in 09eec9f commit. You could take new dll here.

[zzxiang]

Yes! It does work now! Thank you very much for the quick fix!