How to get "CD AB" order from ByteBuf?

[vbnetvbnet]

How can I get a "CD AB" ordered float from ByteBuf? Like:

I know very little about modbus. Can you please help me? Thanks.

[kevinherron]

I'm not sure what that software would consider the order to be by default (maybe DC BA), but try something like this:

short cd = Short.reverseBytes(buffer.readShort());
short ab = Short.reverseBytes(buffer.readShort());
float f = Float.intBitsToFloat((cd << 16) | ab);

Assuming the buffer contains at least 4 bytes (meaning you read at least 2 registers, because each register is 16-bit).

[vbnetvbnet]

@kevinherron Thank you for your reply. I'm trying using your code, but I got the value equal to order BA DC rather than CD AB. Is it because of different default order?

[kevinherron]

Maybe this then?

short ab = buffer.readShort();
short cd = buffer.readShort();
float f = Float.intBitsToFloat((cd << 16 | ab));

[vbnetvbnet]

It works! Thanks!