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[Swift 5] Use BinaryInteger.isMultiple(of:) #29

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jsbean opened this issue Aug 31, 2018 · 0 comments · Fixed by #36

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jsbean commented Aug 31, 2018 •

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Currently, there exists here BinaryInteger.isDivisible(by:), upon which .isEven and .isOdd are implemented.

With SE-0225, BinaryInteger.isMultiple(of:) will exist in the stdlib. Use this instead, for the reasons used in the review.

This will only be applicable as of Swift 5.

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Use BinaryInteger.isMultiple(of:) #36

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jsbean closed this as completed in #36

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