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1.38.0
StpUtil.isLogin()的isLogin显示是false , 但是StpUtil.getTokenInfo()的isLogin显示的true
调用StpUtil.logout(); 后StpUtil.getTokenInfo()的isLogin显示的false
1,调用 StpUtil.login(10001); 2,调用 StpUtil.isLogin() , 调用StpUtil.getTokenInfo() , 结果都正确 3, 调用StpUtil.logout(); 然后再调用StpUtil.isLogin() ,StpUtil.getTokenInfo()
< 备注:如果复现步骤比较复杂,请将 demo 上传到 gitee 并留下地址 >
The text was updated successfully, but these errors were encountered:
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使用版本:
1.38.0
报错信息:
StpUtil.isLogin()的isLogin显示是false , 但是StpUtil.getTokenInfo()的isLogin显示的true
希望结果:
调用StpUtil.logout(); 后StpUtil.getTokenInfo()的isLogin显示的false
复现步骤:
1,调用 StpUtil.login(10001);
2,调用 StpUtil.isLogin() , 调用StpUtil.getTokenInfo() , 结果都正确
3, 调用StpUtil.logout(); 然后再调用StpUtil.isLogin() ,StpUtil.getTokenInfo()
< 备注:如果复现步骤比较复杂,请将 demo 上传到 gitee 并留下地址 >
The text was updated successfully, but these errors were encountered: