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StringToInteger8.java
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StringToInteger8.java
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/**
* Implement atoi to convert a string to an integer.
*
* Hint: Carefully consider all possible input cases. If you want a challenge,
* please do not see below and ask yourself what are the possible input cases.
*
* Notes: It is intended for this problem to be specified vaguely (ie, no given
* input specs). You are responsible to gather all the input requirements up front.
*
* Requirements for atoi:
* The function first discards as many whitespace characters as necessary until
* the first non-whitespace character is found. Then, starting from this
* character, takes an optional initial plus or minus sign followed by as many
* numerical digits as possible, and interprets them as a numerical value.
*
* The string can contain additional characters after those that form the
* integral number, which are ignored and have no effect on the behavior of
* this function.
*
* If the first sequence of non-whitespace characters in str is not a valid
* integral number, or if no such sequence exists because either str is empty
* or it contains only whitespace characters, no conversion is performed.
*
* If no valid conversion could be performed, a zero value is returned. If the
* correct value is out of the range of representable values,
* INT_MAX (2147483647) or INT_MIN (-2147483648) is returned.
*
*/
public class StringToInteger8 {
public int myAtoi(String str) {
if (str == null || str.length() == 0) return 0;
long res = 0; // Initialize result
int sign = 1; // Initialize sign as positive
int i = 0; // Initialize index of first digit
int L = str.length();
while (i < L && str.charAt(i) == ' ') {
i++;
}
// If number is negative, then update sign
boolean hasSign = false;
while (i < L) {
char c = str.charAt(i);
if (c == '-') {
if (hasSign) {
return 0;
} else {
sign = -1;
i++; // Also update index of first digit
hasSign = true;
}
} else if (c == '+') {
if (hasSign) {
return 0;
} else {
i++; // Also update index of first digit
hasSign = true;
}
} else if (c == '0') {
i++; // Also update index of first digit
} else {
break;
}
}
// Iterate through all digits of input string and update result
for (; i < L; ++i) {
if (isNumericChar(str.charAt(i)) == false) break;
res = res * 10 + str.charAt(i) - '0';
if (res > Integer.MAX_VALUE) break;
}
long r = sign*res;
if (r > Integer.MAX_VALUE) {
return Integer.MAX_VALUE;
} else if (r < Integer.MIN_VALUE) {
return Integer.MIN_VALUE;
}
return (int)r;
}
// A utility function to check whether x is numeric
private boolean isNumericChar(char x) {
return (x >= '0' && x <= '9') ? true : false;
}
}