$10 Setting

[HLex79]

Hi Gauthier!

First let me say a big thank you for your awesome soft! It runs smooth on Linux, however I was not able to have it performing well on Windows.

I have a question on the $10 setting, i have read the wiki an i can not figure out the $10=2 value with the buffer?

What should one use, i presume =1? I have strange black boxes appearing in the DRO field recently while hovering over with the mouse cursor.

BTW is there a setting =0 for this value?

Thanks a lot,

Lex.

[fra589]

Hi Lex,

The $10 parameter is used to define the elements returned by the "?" Command.

This is a binary mask where only the first 2 bits are used.

• Bit 0 defines whether you want to receive the working position or the machine position: If the bit value is 0, "?" returns the working position (WPOS), if it is at 1, "?" returns the machine position (MPOS).
• If the bit 1 value is 1, the state of the Grbl's internal buffers (planner and serial RX available buffer) are added to the result of the "?" Command.

The cn5X++ program itself manages and force the value of the parameter $10: Depending on the choice of the "Machine / View working positions (WPOS)" or "Machine / View machine positions (MPOS)" menu.
Bit 1 is alwais set to 1 so that cn5X++ can know the state of the Grbl buffers.

@++;
Gauthier

[HLex79]

Hi Gauthier,

Thanks for your explanations! I have set it back to zero and cn5X is back as new 😁
Best,

Lex