Given the root
of a binary tree, determine if it is a complete binary tree.
In a complete binary tree, every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1
and 2h
nodes inclusive at the last level h
.
Input: root = [1,2,3,4,5,6] Output: true Explanation: Every level before the last is full (ie. levels with node-values {1} and {2, 3}), and all nodes in the last level ({4, 5, 6}) are as far left as possible.
Input: root = [1,2,3,4,5,null,7] Output: false Explanation: The node with value 7 isn't as far left as possible.
- The number of nodes in the tree is in the range
[1, 100]
. 1 <= Node.val <= 1000
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isCompleteTree(self, root: Optional[TreeNode]) -> bool:
nodes = [root]
depth = 0
while True:
children = []
if nodes[0] == None:
return True
if len(nodes) != 2 ** depth:
return False
for node in nodes:
if node is not None:
children.append(node.left)
children.append(node.right)
for i in range(1, len(children)):
if children[i - 1] is None and children[i] is not None:
return False
nodes = children
depth += 1