Problem with opening local file with "compression=..."

[seandavi]

See behavior difference with "file://filename" uri vs "filename" uri with compression.

>>> print(upath.__version__)
0.1.4
>>> a = UPath('abc.json.gz')
>>> a.open('wb', compression='gzip')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: open() got an unexpected keyword argument 'compression'
>>> 
>>> a = UPath('file:///tmp/abc.json.gz')
>>> a.open('wb', compression='gzip')
<gzip fsspec.implementations.local.LocalFileOpener object at 0x1028548b0 0x1034b1f40>

[ap--]

Thank you for reporting @seandavi ❤️

We should align the method signatures and raise a warning for stdlib pathlib in this case.

Would you be willing to work on a PR?

Cheers,
Andreas