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StoneGameIII.java
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StoneGameIII.java
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package dynamic_programming;
/**
* Created by gouthamvidyapradhan on 16/04/2020 Alice and Bob continue their games with piles of
* stones. There are several stones arranged in a row, and each stone has an associated value which
* is an integer given in the array stoneValue.
*
* <p>Alice and Bob take turns, with Alice starting first. On each player's turn, that player can
* take 1, 2 or 3 stones from the first remaining stones in the row.
*
* <p>The score of each player is the sum of values of the stones taken. The score of each player is
* 0 initially.
*
* <p>The objective of the game is to end with the highest score, and the winner is the player with
* the highest score and there could be a tie. The game continues until all the stones have been
* taken.
*
* <p>Assume Alice and Bob play optimally.
*
* <p>Return "Alice" if Alice will win, "Bob" if Bob will win or "Tie" if they end the game with the
* same score.
*
* <p>Example 1:
*
* <p>Input: values = [1,2,3,7] Output: "Bob" Explanation: Alice will always lose. Her best move
* will be to take three piles and the score become 6. Now the score of Bob is 7 and Bob wins.
* Example 2:
*
* <p>Input: values = [1,2,3,-9] Output: "Alice" Explanation: Alice must choose all the three piles
* at the first move to win and leave Bob with negative score. If Alice chooses one pile her score
* will be 1 and the next move Bob's score becomes 5. The next move Alice will take the pile with
* value = -9 and lose. If Alice chooses two piles her score will be 3 and the next move Bob's score
* becomes 3. The next move Alice will take the pile with value = -9 and also lose. Remember that
* both play optimally so here Alice will choose the scenario that makes her win. Example 3:
*
* <p>Input: values = [1,2,3,6] Output: "Tie" Explanation: Alice cannot win this game. She can end
* the game in a draw if she decided to choose all the first three piles, otherwise she will lose.
* Example 4:
*
* <p>Input: values = [1,2,3,-1,-2,-3,7] Output: "Alice" Example 5:
*
* <p>Input: values = [-1,-2,-3] Output: "Tie"
*
* <p>Constraints:
*
* <p>1 <= values.length <= 50000 -1000 <= values[i] <= 1000
*/
public class StoneGameIII {
private class State {
int a, b;
State(int a, int b) {
this.a = a;
this.b = b;
}
}
public static void main(String[] args) {
int[] V = {-1, -2, -3};
System.out.println(new StoneGameIII().stoneGameIII(V));
}
private State[][] DP;
public String stoneGameIII(int[] stoneValue) {
DP = new State[2][stoneValue.length];
State result = dp(0, 0, stoneValue);
return (result.a > result.b) ? "Alice" : (result.b > result.a) ? "Bob" : "Tie";
}
private State dp(int i, int p, int[] stoneValue) {
if (i >= stoneValue.length) return new State(0, 0);
else if (DP[p][i] != null) return DP[p][i];
else {
int sum = 0;
for (int j = 0; j < 3; j++) {
if (i + j >= stoneValue.length) break;
sum += (stoneValue[i + j]);
State result = dp(i + j + 1, (p + 1) % 2, stoneValue);
if (p == 0) {
if (DP[p][i] == null) {
DP[p][i] = new State((sum + result.a), result.b);
} else if (DP[p][i].a < (sum + result.a)) {
DP[p][i] = new State((sum + result.a), result.b);
}
} else {
if (DP[p][i] == null) {
DP[p][i] = new State(result.a, (sum + result.b));
} else if (DP[p][i].b < (sum + result.b)) {
DP[p][i] = new State(result.a, (sum + result.b));
}
}
}
return DP[p][i];
}
}
}