KeyError if parameter is empty

[billdesk]

import os
uri = os.environ['REQUEST_URI']

from furl import furl
f = furl(uri)
print f.args['product']
print f.args['category']

If current uri is /product.py?product=12&category=2

Then it prints 12 and 2

But if current uri is /product.py?product=12
it throws KeyError

[gruns]

Unless I misunderstand you, this is the expected behavior of furl.args.

furl.args is a dictionary (an orderedmultidict to be specific), and just like a
standard Python dictionary, KeyError is raised on a missing key.

>>> d = {1:1}
>>> d[2]
Traceback (most recent call last):
  ...
KeyError: 2
>>>
>>> from furl import furl
>>> f = furl('http://www.google.com/?1=1')
>>> dict(f.args)
{'1': '1'}
>>> f.args[2]
Traceback (most recent call last):
  ...
KeyError: 2

To avoid raising a KeyError on a missing key, use the get() method, just like
the get() method of standard Python dictionaries.

>>> from furl import furl
>>> f = furl('http://www.google.com/?1=1')
>>> dict(f.args)
{'1': '1'}
>>> print(f.args.get(2))
None

Or, in your example

import os
uri = os.environ['REQUEST_URI']

from furl import furl
f = furl(uri)
print f.args.get('product')
print f.args.get('category')

Does that answer your question?

[gruns]

Little bump -- does my previous question answer your question, @billdesk?

[gruns]

Closing due to inactivity.

Please reopen if your query was unanswered above.