Possible error in transform.Rmd / tbl_dfs now do partial matching?

[khumph]

In the Data Transformation chapter, the following is written:

• When you extract a variable with $, tbl_dfs never do partial
  matching. They'll throw an error if the column doesn't exist:

df <- data.frame(abc = 1)
df$a

df2 <- data_frame(abc = 1)
df2$a

However the live version of the r4ds website (immediately above http://r4ds.had.co.nz/transform.html#dplyr-verbs) implies that partial matching does work. At any rate, it doesn't throw an error, as was meant to be illustrated.

I get the same in my R console:

df <- data.frame(abc = 1)
df$a
#> [1] 1

df2 <- data_frame(abc = 1)
df2$a
#> [1] 1

Do tbl_dfs now do partial matching with $?

FYI:

sessionInfo()
#> R version 3.2.4 (2016-03-10)
#> Platform: x86_64-apple-darwin13.4.0 (64-bit)
#> Running under: OS X 10.11.4 (El Capitan)
#> 
#> locale:
#> [1] en_US.UTF-8/en_US.UTF-8/en_US.UTF-8/C/en_US.UTF-8/en_US.UTF-8
#> 
#> attached base packages:
#> [1] stats     graphics  grDevices utils     datasets  methods   base     
#> 
#> other attached packages:
#> [1] reprex_0.0.0.9001 dplyr_0.4.3      
#> 
#> loaded via a namespace (and not attached):
#>  [1] Rcpp_0.12.4     knitr_1.12.3    magrittr_1.5    splines_3.2.4  
#>  [5] MASS_7.3-45     lattice_0.20-33 R6_2.1.2        minqa_1.2.4    
#>  [9] stringr_1.0.0   tools_3.2.4     parallel_3.2.4  grid_3.2.4     
#> [13] nlme_3.1-125    DBI_0.3.1       clipr_0.2.0     htmltools_0.3.5
#> [17] lme4_1.1-11     lazyeval_0.1.10 assertthat_0.1  digest_0.6.9   
#> [21] Matrix_1.2-4    nloptr_1.0.4    formatR_1.3     evaluate_0.8.3 
#> [25] rmarkdown_0.9.5 stringi_1.0-1

[hadley]

It's fixed in the dev version of dplyr.