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On page 349 (see the screenshot),
shouldn't Store f :: s -> Store f s be Store f :: s -> Store (s -> a) s?
The expression on the right-hand side of :: is a type and apparently f is a value with type s -> a.
The text was updated successfully, but these errors were encountered:
On page 349 (see the screenshot),
shouldn't
Store f :: s -> Store f s
beStore f :: s -> Store (s -> a) s
?The expression on the right-hand side of
::
is a type and apparentlyf
is a value with types -> a
.The text was updated successfully, but these errors were encountered: