https://leetcode.com/problems/flatten-binary-tree-to-linked-list/
Given the root of a binary tree, flatten the tree into a "linked list":
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The "linked list" should use the same TreeNode class where the right child pointer points to the next node in the list and the left child pointer is always null.
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The "linked list" should be in the same order as a pre-order traversal of the binary tree.
Example 1:
Input: root = [1,2,5,3,4,null,6]
Output: [1,null,2,null,3,null,4,null,5,null,6]
Example 2:
Input: root = []
Output: []
Example 3:
Input: root = [0]
Output: [0]
The number of nodes in the tree is in the range [0, 2000].
-100 <= Node.val <= 100
Follow up: Can you flatten the tree in-place (with O(1) extra space)?