Year > 9999?

[retorquere]

EDTF L1 (not the WD) accepts y170000002 as a valid date, how must I pass that to edtf.js? I've tried removing the leading y but that doesn't do it.

[inukshuk]

See section 4.6 years exceeding four digits. The syntax is now with a capital Y, i.e., Y170000002 or using exponential form Y17E7.

[SylvainBigonneau]

Shouldn't edtf('9999').next() return a Year then ?

Because right now it seems a little confusing that:

let date = edtf('9999').next()
let edtfString = date.edtf // '10000'
let dateCopy = edtf(edtfString)

triggers an error since "10000" is an incorrect EDTF notation, if I understand correctly?

[inukshuk]

Hmm, that's a good question. I think .next() should probably still return a Date. But when formatted to a string it should return it as Y10000. This is definitely tricky...