This repository has been archived by the owner on Nov 26, 2017. It is now read-only.
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I think that it would be enough to do
if (is_string($key) && $id)
. If the condition fails for $key it will fail for is_string($key) too.There was a problem hiding this comment.
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But if $key would not exist you would then get a Notice: Undefined variable: key
That's why $key is tested first and cannot be left.
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Yes, but $key is by default null. I can't see any case when $key is not defined in this context.
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You are right (I was wrong).