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evaluate Fun on `FloatRange` #57

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goretkin opened this issue Dec 4, 2014 · 0 comments

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goretkin commented Dec 4, 2014

currently gives a stack overflow

julia> x = Fun(identity)
Fun{UltrasphericalSpace{0},Float64}([0.0,1.0],UltrasphericalSpace{0}(Interval{Float64}(-1.0,1.0)))

julia> x[1.0:0.1:5.0]
ERROR: stack overflow

If you evaluate the FloatRange as an array before ( [1.:.1:5.]), then there's no problem.

This stack trace I wasn't able to reproduce may help

julia> vec(yn)[1][3:.01:4]
ERROR: stack overflow
 in abs at operators.jl:359
 in clenshaw at /Users/goretkin/.julia/v0.3/ApproxFun/src/LinearAlgebra/clenshaw.jl:12
 in clenshaw at /Users/goretkin/.julia/v0.3/ApproxFun/src/LinearAlgebra/clenshaw.jl:15 (repeats 52398 times)
 in getindex at /Users/goretkin/.julia/v0.3/ApproxFun/src/Fun/Fun.jl:76

The text was updated successfully, but these errors were encountered:

dlfivefifty closed this as completed in

5825acc

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