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In such case: _s1 = "b", s2 = "acca", s3 = "abcba"_, it would return true.
This is related to:
for (int i = 1; i <= N; ++i) dp[i][0] = s2[i-1] == s3[i-1]; for (int j = 1; j <= M; ++j) dp[0][j] = s1[j-1] == s3[j-1];
The text was updated successfully, but these errors were encountered:
Fix a bug #14 reported by imley.
130dd01
In such case: s1 = "b", s2 = "acca", s3 = "abcba", it would return true.
Thank you so much for your bug report. Yes, there is a problem. I have fixed the bug. Could you please check it again? Thank you. 👍
Sorry, something went wrong.
Yeah, this should have fix it:) Thanks for sharing us your solutions.
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In such case: _s1 = "b", s2 = "acca", s3 = "abcba"_, it would return true.
This is related to:
The text was updated successfully, but these errors were encountered: