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你的方式会让相同的数也会算一对,怎么避免计算这个相同的数对呢? 我在if else把 aux[i - l] < aux[j - l] 改成 > ... 并且添加了处理相同数的else . 但是出现了更大的问题(很多数对不被计算 了) 请问该怎么处理呢?谢谢 :)
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你的方式会让相同的数也会算一对,怎么避免计算这个相同的数对呢?
我在if else把 aux[i - l] < aux[j - l] 改成 > ... 并且添加了处理相同数的else .
但是出现了更大的问题(很多数对不被计算 了)
请问该怎么处理呢?谢谢 :)
The text was updated successfully, but these errors were encountered: