$regex operator called with non regular expression

[jindalrohit]

I'm trying to search string using regex as below:

db.find({ consignee: { $regex: /test/ } }, function (err, docs) {
console.log(docs);
});

But it is throwing error
Error: $regex operator called with non regular expression

[JamesMGreene]

Can you consistently reproduce this error? Seems very odd.

[Janglee123]

@jindalrohit have you figured out how to solve this issue ?

[Janglee123]

@JamesMGreene I can reproduce this error now. The below function is used to find a book from the database based on the title of a book with regex.

Library.searchBook = function (name) {
    query = new RegExp(name, 'i');
    console.log({query});
    db.find({ title: { $regex: query } }, (err, result) => {
        console.log({result});
        if (err){
            console.error(err);
            return;
        }
        result.forEach(row => {
            Library.loadBook(row);
        });
    });
};

The above function gives an error every time it gets executed. The function was working perfectly before, I don't know for which version. Now it is throwing error Error: $regex operator called with non regular expression. Current version is 1.8.0. Here is the screenshot of the output and you can see the code here.

[zerooverture]

I have the same problem，and $where tip
$where function must return boolean ，
But I did return boolean

[lechatthecat]

Same error. No idea how to remove this error.

[avalla]

I cannot find any solution to this issue

[TheDanielMoli]

Same issue here:

{ $or: [ {email: { $regex: `.*${search}.*`, $options: 'i' }}, {name: { $regex: `.*${search}.*`, $options: 'i' }} ] };

[avalla]

I replaced nedb with sqlite, performance are better and migration was not so painful

[codernoder]

Use { $regex: new RegExp('test') } instead { $regex: /test/ }