为什么urllib.error.URLError捕获不了异常

[dirtyluke]

我的代码在这里
用的是python3.6，抓取主播信息时老是报URLError错误，但是却捕获不了，能帮忙看一下吗

[octans]

@dirtyluke 贴一下你的报错信息，看能不能尽量详细一些

[dirtyluke]

不好意思现在才回复。。。
74339197:html parse error in getUserData
Traceback (most recent call last):
File "D:\Program Files\Python\Python36\lib\urllib\request.py", line 1314, in do_open
h.request(req.get_method(), req.selector, req.data, headers)
File "D:\Program Files\Python\Python36\lib\http\client.py", line 1155, in request
self._send_request(method, url, body, headers)
File "D:\Program Files\Python\Python36\lib\http\client.py", line 1200, in _send_request
self.endheaders(body)
File "D:\Program Files\Python\Python36\lib\http\client.py", line 1151, in endheaders
self._send_output(message_body)
File "D:\Program Files\Python\Python36\lib\http\client.py", line 983, in _send_output
self.send(msg)
File "D:\Program Files\Python\Python36\lib\http\client.py", line 926, in send
self.connect()
File "D:\Program Files\Python\Python36\lib\http\client.py", line 898, in connect
(self.host,self.port), self.timeout, self.source_address)
File "D:\Program Files\Python\Python36\lib\socket.py", line 711, in create_connection
raise err
File "D:\Program Files\Python\Python36\lib\socket.py", line 702, in create_connection
sock.connect(sa)
socket.timeout: timed out

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
File "huajiao.py", line 218, in
main(sys.argv)
File "huajiao.py", line 196, in main
spiderUserDatas()
File "huajiao.py", line 130, in spiderUserDatas
userId = getUserId(liveId)
File "huajiao.py", line 29, in getUserId
html = urlopen("http://www.huajiao.com/l/" + str(liveId),timeout=1)
File "D:\Program Files\Python\Python36\lib\urllib\request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "D:\Program Files\Python\Python36\lib\urllib\request.py", line 526, in open
response = self._open(req, data)
File "D:\Program Files\Python\Python36\lib\urllib\request.py", line 544, in _open
'_open', req)
File "D:\Program Files\Python\Python36\lib\urllib\request.py", line 504, in _call_chain
result = func(*args)
File "D:\Program Files\Python\Python36\lib\urllib\request.py", line 1342, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "D:\Program Files\Python\Python36\lib\urllib\request.py", line 1316, in do_open
raise URLError(err)
urllib.error.URLError:

[dirtyluke]

解决了，自己前面设置的超时设置太长了，网上说的是可能服务器自动断开了连接，但客户端不知道，才产生的错误，把超时时间缩短就能捕获了