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Declare Implementation
Michael Damatov edited this page Jan 17, 2024
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Declare an implementation of the IEqualityOperators<T, T, bool>
interface when one of the following conditions is met:
- The type is a class that already implements the
IEquatable<T>
interface. - The type is a struct that already implements the
IEquatable<T>
interface. - The type is a record.
- The context action does not add the equality operators. It only declares the implementation of the
IEqualityOperators<T, T, bool>
interface. The equality operators must be implemented manually or by using the ReSharper context actions. - The context action is only available when C# 11 or higher is used with the the framework, which has the
IEqualityOperators<TSelf,TOther,TResult>
interface.
- Only classes, which implement the
IEquatable<T>
interface are supported. Derived classes are not analyzed. - Only classes, which implement the
IEquatable<T>
interface are supported. Interfaces that extend theIEquatable<T>
interface are not considered (rare use case).
Declare an implementation of the IComparisonOperators<T, T, bool>
interface when one of the following conditions is met:
- The type is a class that already implements the
IComparable<T>
interface. - The type is a struct that already implements the
IComparable<T>
interface. - The type is a record.
- The context action does not add the equality operators. It only declares the implementation of the
IComparisonOperators<T, T, bool>
interface. The equality operators must be implemented manually or by using the ReSharper context actions. - The context action is only available when C# 11 or higher is used with the the framework, which has the
IComparisonOperators<TSelf,TOther,TResult>
interface.
- Only classes, which implement the
IComparable<T>
interface are supported. Derived classes are not analyzed. - Only classes, which implement the
IComparable<T>
interface are supported. Interfaces that extend theIComparable<T>
interface are not considered (rare use case).