unzip return value

[cstepper]

Hi Gabor,
I really like the zip package.

We'd like to use the unzip command and need the path to the unzipped file.

The utils::unzip function returns:
Otherwise for the "internal" method, a character vector of the filepaths extracted to, invisibly.

In the zip::unzip the return is invisible().

I'm not familiar with the calling of C code in the unzip function

.Call(c_R_zip_unzip, zipfile, files, overwrite, junkpaths, exdir)

and what it does return.

If it would be possible to implement a return as a character vector of the filepaths extracted to, it would be great.

Thanks, Christoph

[gaborcsardi]

Right, that would indeed make sense. It is not too hard to work around it, though, just call zip_list() before extracting and use the filename column:

❯ zip::zip("/tmp/x.zip", "works/zip/R")
❯ exdir <- tempfile()
❯ zip::unzip("/tmp/x.zip", exdir= exdir)
❯ files <- file.path(exdir, zip::zip_list("/tmp/x.zip")$filename)
❯ file.exists(files)
[1] TRUE TRUE TRUE TRUE TRUE

It should not be too slow, because AFAIR zip_list() does not go through the whole file, it only checks the index.

[cstepper]

Hi Gabar,
thanks for that hint. Used the work around for now.
Would be nice to see the feature in future :)
Cheers, Christoph

[gaborcsardi]

Yes, will add that at some point, it will probably return a data frame, though, to be able to add more data to it.

[cstepper]

perfect!

[gaborcsardi]

Wait, don't close this, because then I'll forget. :)