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sync.go
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sync.go
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// Copyright 2019 The go-ethereum Authors
// This file is part of the go-ethereum library.
//
// The go-ethereum library is free software: you can redistribute it and/or modify
// it under the terms of the GNU Lesser General Public License as published by
// the Free Software Foundation, either version 3 of the License, or
// (at your option) any later version.
//
// The go-ethereum library is distributed in the hope that it will be useful,
// but WITHOUT ANY WARRANTY; without even the implied warranty of
// MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
// GNU Lesser General Public License for more details.
//
// You should have received a copy of the GNU Lesser General Public License
// along with the go-ethereum library. If not, see <http://www.gnu.org/licenses/>.
package dnsdisc
import (
"context"
"math/rand"
"time"
"github.com/rethereum-blockchain/go-rethereum/common/mclock"
"github.com/rethereum-blockchain/go-rethereum/p2p/enode"
)
// This is the number of consecutive leaf requests that may fail before
// we consider re-resolving the tree root.
const rootRecheckFailCount = 5
// clientTree is a full tree being synced.
type clientTree struct {
c *Client
loc *linkEntry // link to this tree
lastRootCheck mclock.AbsTime // last revalidation of root
leafFailCount int
rootFailCount int
root *rootEntry
enrs *subtreeSync
links *subtreeSync
lc *linkCache // tracks all links between all trees
curLinks map[string]struct{} // links contained in this tree
linkGCRoot string // root on which last link GC has run
}
func newClientTree(c *Client, lc *linkCache, loc *linkEntry) *clientTree {
return &clientTree{c: c, lc: lc, loc: loc}
}
// syncAll retrieves all entries of the tree.
func (ct *clientTree) syncAll(dest map[string]entry) error {
if err := ct.updateRoot(context.Background()); err != nil {
return err
}
if err := ct.links.resolveAll(dest); err != nil {
return err
}
if err := ct.enrs.resolveAll(dest); err != nil {
return err
}
return nil
}
// syncRandom retrieves a single entry of the tree. The Node return value
// is non-nil if the entry was a node.
func (ct *clientTree) syncRandom(ctx context.Context) (n *enode.Node, err error) {
if ct.rootUpdateDue() {
if err := ct.updateRoot(ctx); err != nil {
return nil, err
}
}
// Update fail counter for leaf request errors.
defer func() {
if err != nil {
ct.leafFailCount++
}
}()
// Link tree sync has priority, run it to completion before syncing ENRs.
if !ct.links.done() {
err := ct.syncNextLink(ctx)
return nil, err
}
ct.gcLinks()
// Sync next random entry in ENR tree. Once every node has been visited, we simply
// start over. This is fine because entries are cached internally by the client LRU
// also by DNS resolvers.
if ct.enrs.done() {
ct.enrs = newSubtreeSync(ct.c, ct.loc, ct.root.eroot, false)
}
return ct.syncNextRandomENR(ctx)
}
// canSyncRandom checks if any meaningful action can be performed by syncRandom.
func (ct *clientTree) canSyncRandom() bool {
// Note: the check for non-zero leaf count is very important here.
// If we're done syncing all nodes, and no leaves were found, the tree
// is empty and we can't use it for sync.
return ct.rootUpdateDue() || !ct.links.done() || !ct.enrs.done() || ct.enrs.leaves != 0
}
// gcLinks removes outdated links from the global link cache. GC runs once
// when the link sync finishes.
func (ct *clientTree) gcLinks() {
if !ct.links.done() || ct.root.lroot == ct.linkGCRoot {
return
}
ct.lc.resetLinks(ct.loc.str, ct.curLinks)
ct.linkGCRoot = ct.root.lroot
}
func (ct *clientTree) syncNextLink(ctx context.Context) error {
hash := ct.links.missing[0]
e, err := ct.links.resolveNext(ctx, hash)
if err != nil {
return err
}
ct.links.missing = ct.links.missing[1:]
if dest, ok := e.(*linkEntry); ok {
ct.lc.addLink(ct.loc.str, dest.str)
ct.curLinks[dest.str] = struct{}{}
}
return nil
}
func (ct *clientTree) syncNextRandomENR(ctx context.Context) (*enode.Node, error) {
index := rand.Intn(len(ct.enrs.missing))
hash := ct.enrs.missing[index]
e, err := ct.enrs.resolveNext(ctx, hash)
if err != nil {
return nil, err
}
ct.enrs.missing = removeHash(ct.enrs.missing, index)
if ee, ok := e.(*enrEntry); ok {
return ee.node, nil
}
return nil, nil
}
func (ct *clientTree) String() string {
return ct.loc.String()
}
// removeHash removes the element at index from h.
func removeHash(h []string, index int) []string {
if len(h) == 1 {
return nil
}
last := len(h) - 1
if index < last {
h[index] = h[last]
h[last] = ""
}
return h[:last]
}
// updateRoot ensures that the given tree has an up-to-date root.
func (ct *clientTree) updateRoot(ctx context.Context) error {
if !ct.slowdownRootUpdate(ctx) {
return ctx.Err()
}
ct.lastRootCheck = ct.c.clock.Now()
ctx, cancel := context.WithTimeout(ctx, ct.c.cfg.Timeout)
defer cancel()
root, err := ct.c.resolveRoot(ctx, ct.loc)
if err != nil {
ct.rootFailCount++
return err
}
ct.root = &root
ct.rootFailCount = 0
ct.leafFailCount = 0
// Invalidate subtrees if changed.
if ct.links == nil || root.lroot != ct.links.root {
ct.links = newSubtreeSync(ct.c, ct.loc, root.lroot, true)
ct.curLinks = make(map[string]struct{})
}
if ct.enrs == nil || root.eroot != ct.enrs.root {
ct.enrs = newSubtreeSync(ct.c, ct.loc, root.eroot, false)
}
return nil
}
// rootUpdateDue returns true when a root update is needed.
func (ct *clientTree) rootUpdateDue() bool {
tooManyFailures := ct.leafFailCount > rootRecheckFailCount
scheduledCheck := ct.c.clock.Now() >= ct.nextScheduledRootCheck()
return ct.root == nil || tooManyFailures || scheduledCheck
}
func (ct *clientTree) nextScheduledRootCheck() mclock.AbsTime {
return ct.lastRootCheck.Add(ct.c.cfg.RecheckInterval)
}
// slowdownRootUpdate applies a delay to root resolution if is tried
// too frequently. This avoids busy polling when the client is offline.
// Returns true if the timeout passed, false if sync was canceled.
func (ct *clientTree) slowdownRootUpdate(ctx context.Context) bool {
var delay time.Duration
switch {
case ct.rootFailCount > 20:
delay = 10 * time.Second
case ct.rootFailCount > 5:
delay = 5 * time.Second
default:
return true
}
timeout := ct.c.clock.NewTimer(delay)
defer timeout.Stop()
select {
case <-timeout.C():
return true
case <-ctx.Done():
return false
}
}
// subtreeSync is the sync of an ENR or link subtree.
type subtreeSync struct {
c *Client
loc *linkEntry
root string
missing []string // missing tree node hashes
link bool // true if this sync is for the link tree
leaves int // counter of synced leaves
}
func newSubtreeSync(c *Client, loc *linkEntry, root string, link bool) *subtreeSync {
return &subtreeSync{c, loc, root, []string{root}, link, 0}
}
func (ts *subtreeSync) done() bool {
return len(ts.missing) == 0
}
func (ts *subtreeSync) resolveAll(dest map[string]entry) error {
for !ts.done() {
hash := ts.missing[0]
ctx, cancel := context.WithTimeout(context.Background(), ts.c.cfg.Timeout)
e, err := ts.resolveNext(ctx, hash)
cancel()
if err != nil {
return err
}
dest[hash] = e
ts.missing = ts.missing[1:]
}
return nil
}
func (ts *subtreeSync) resolveNext(ctx context.Context, hash string) (entry, error) {
e, err := ts.c.resolveEntry(ctx, ts.loc.domain, hash)
if err != nil {
return nil, err
}
switch e := e.(type) {
case *enrEntry:
if ts.link {
return nil, errENRInLinkTree
}
ts.leaves++
case *linkEntry:
if !ts.link {
return nil, errLinkInENRTree
}
ts.leaves++
case *branchEntry:
ts.missing = append(ts.missing, e.children...)
}
return e, nil
}
// linkCache tracks links between trees.
type linkCache struct {
backrefs map[string]map[string]struct{}
changed bool
}
func (lc *linkCache) isReferenced(r string) bool {
return len(lc.backrefs[r]) != 0
}
func (lc *linkCache) addLink(from, to string) {
if _, ok := lc.backrefs[to][from]; ok {
return
}
if lc.backrefs == nil {
lc.backrefs = make(map[string]map[string]struct{})
}
if _, ok := lc.backrefs[to]; !ok {
lc.backrefs[to] = make(map[string]struct{})
}
lc.backrefs[to][from] = struct{}{}
lc.changed = true
}
// resetLinks clears all links of the given tree.
func (lc *linkCache) resetLinks(from string, keep map[string]struct{}) {
stk := []string{from}
for len(stk) > 0 {
item := stk[len(stk)-1]
stk = stk[:len(stk)-1]
for r, refs := range lc.backrefs {
if _, ok := keep[r]; ok {
continue
}
if _, ok := refs[item]; !ok {
continue
}
lc.changed = true
delete(refs, item)
if len(refs) == 0 {
delete(lc.backrefs, r)
stk = append(stk, r)
}
}
}
}