Given two arrays, write a function to compute their intersection.
Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2,2]
Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9]
- Each element in the result should appear as many times as it shows in both arrays.
- The result can be in any order.
- What if the given array is already sorted? How would you optimize your algorithm?
- What if nums1's size is small compared to nums2's size? Which algorithm is better?
- What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
/**
* @param {number[]} nums1
* @param {number[]} nums2
* @return {number[]}
*/
var intersect = function(nums1, nums2) {
var result = [];
var searched = [];
for(var i =0; i<nums1.length;++i){
for(var j= 0; j<nums2.length;++j){
if(nums1[i] === nums2[j] && searched[j] !=1){
result.push(nums1[i]);
searched[j] = 1;
break;
}
}
}
return result;
};