Big(1).divideWithMathContext(Big(3), new MC(0, RoundingMode.CEILING)).numberValue()

[qingfengmy]

Describe the bug
Big(1).divideWithMathContext(Big(3), new MC(0, RoundingMode.CEILING)).numberValue()

                throw new RangeError('Non-terminating decimal expansion; no exact representable decimal result.');

1/3 ceiling

i want the result is 1. What should I do?

[srknzl]

Hi,

Doing the same thing also throws in java. It is because precision is 0. As I know, 0 precision means unlimited precision and means give me the exact result. So, we are asking the exact result from this operation but the exact result cannot be obtained with a non-terminating decimal expansion(0.3333...).

This code

new BigDecimal("1").divide(new BigDecimal("3"), new MathContext(0, RoundingMode.CEILING));

throws

Exception in thread "main" java.lang.ArithmeticException: Non-terminating decimal expansion; no exact representable decimal result.
	at java.math.BigDecimal.divide(BigDecimal.java:1693)
	at java.math.BigDecimal.divide(BigDecimal.java:1726)
	at Main.main(Main.java:23)

You can do this:

Big(1).divide(Big(3), undefined, RoundingMode.CEILING).numberValue()
// 1

which is equiavalent of Java's:

new BigDecimal(1).divide(new BigDecimal(3), RoundingMode.CEILING).intValue()
// 1

[srknzl]

Closing because I think my reply solves your problem, reopen the issue if it does not.