Special case not managed by the parser, when an expression is split without a backslash and the second line is dedented.

[martinett]

Here is a minimal valid python code sample for the parser to detect an error :

if True:
    l[i+
1]

And here is a minimal code to get the error :

from tree_sitter import Language, Parser

Language.build_library("build/my-languages.so", ["parsers/tree-sitter-python"])
PY_LANGUAGE = Language("build/my-languages.so", "python")
parser = Parser()
parser.set_language(PY_LANGUAGE)

code = "if True:\n    l[i+\n1]"
tree = parser.parse(bytes(code,"utf-8"))
print(tree.root_node.sexp())
print(tree.root_node.children[1])
print(tree.root_node.children[0].children[3])

(module (if_statement condition: (true) (ERROR (identifier) (identifier)) consequence: (block)) (ERROR (integer)))
<Node type=ERROR, start_point=(2, 0), end_point=(2, 2)>
<Node type=ERROR, start_point=(1, 4), end_point=(1, 8)>

Whatever the indentation of the 1] line, if it is less indented than the l[i+ line, the parser detects an error.
But this code is valid, it works and the ast library has no problem parsing it.

[martinett]

I don't think it is a parser python version problem, but I couldn't find how to check this.

[ObserverOfTime]

That seems like a parser issue, if still relevant.

[martinett]

So there is no solution to this? I can't deal with codes which contain this pattern.

[amaanq]

it is a parser error, feel free to PR a fix yourself in the parser repo