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// 1. 将Union类型变成函数的联合函数类型 type ToUnionFunction<T> = T extends unknown ? (arg: T) => void : never; // 2. 联合函数的类型,怎么就变成了交叉参数的一个函数? // ts对应PR:https://github.com/Microsoft/TypeScript/pull/21496 type UnionToIntersection<U> = ToUnionFunction<U> extends (arg: infer Args) => void ? Args : never;
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