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这样的话:
d/1
d/2
or/2
3d4
d(3, 4)
(&d/2).(3, 4)
count/1
count/2
has?/2
at/2
count/*
count $list
$list count \($x -> $x > 50)
$list has? 42
$list at 2
需要考虑:
foo ($baz bar $qux)
foo $baz bar $qux
d/*
foo 3d10
foo (3d10)
The text was updated successfully, but these errors were encountered:
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这样的话:
d/1
、d/2
、or/2
等等这些运算符都变为通常函数:d/2
:既可以3d4
,也可以d(3, 4)
,还可以(&d/2).(3, 4)
。count/1
、count/2
、has?/2
、at/2
也成了运算符:count/*
:count $list
、$list count \($x -> $x > 50)
;has?/2
:$list has? 42
;at/2
:$list at 2
。需要考虑:
foo ($baz bar $qux)
vsfoo $baz bar $qux
)?d/*
(如foo 3d10
vsfoo (3d10)
)?The text was updated successfully, but these errors were encountered: