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GFG_LargestBST.cpp
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GFG_LargestBST.cpp
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/*
https://practice.geeksforgeeks.org/problems/largest-bst/1
Largest BST
https://leetcode.com/problems/largest-bst-subtree/
*/
//{ Driver Code Starts
//Initial Template for C++
#include <bits/stdc++.h>
using namespace std;
#define MAX_HEIGHT 100000
// Tree Node
struct Node {
int data;
Node* left;
Node* right;
};
// Utility function to create a new Tree Node
Node* newNode(int val) {
Node* temp = new Node;
temp->data = val;
temp->left = NULL;
temp->right = NULL;
return temp;
}
// Function to Build Tree
Node* buildTree(string str) {
// Corner Case
if (str.length() == 0 || str[0] == 'N') return NULL;
// Creating vector of strings from input
// string after spliting by space
vector<string> ip;
istringstream iss(str);
for (string str; iss >> str;) ip.push_back(str);
// Create the root of the tree
Node* root = newNode(stoi(ip[0]));
// Push the root to the queue
queue<Node*> queue;
queue.push(root);
// Starting from the second element
int i = 1;
while (!queue.empty() && i < ip.size()) {
// Get and remove the front of the queue
Node* currNode = queue.front();
queue.pop();
// Get the current node's value from the string
string currVal = ip[i];
// If the left child is not null
if (currVal != "N") {
// Create the left child for the current node
currNode->left = newNode(stoi(currVal));
// Push it to the queue
queue.push(currNode->left);
}
// For the right child
i++;
if (i >= ip.size()) break;
currVal = ip[i];
// If the right child is not null
if (currVal != "N") {
// Create the right child for the current node
currNode->right = newNode(stoi(currVal));
// Push it to the queue
queue.push(currNode->right);
}
i++;
}
return root;
}
// } Driver Code Ends
/* Tree node structure used in the program
struct Node {
int data;
Node *left;
Node *right;
Node(int val) {
data = val;
left = right = NULL;
}
};*/
// #define minid 0
// #define maxid 1
// #define size 2
enum ids {minval, maxval, size};
class Solution{
public:
/*You are required to complete this method */
// Return the size of the largest sub-tree which is also a BST
int ans=1;
int largestBst(Node *root)
{
if(!root)
return 0;
checkLargestBST(root);
return ans;
}
vector<int> checkLargestBST(Node* root)
{
// min_value, max_value, size of bst;
if(!root)
return {INT_MAX, INT_MIN, 0};
if(!root->left and !root->right)
return {root->data, root->data, 1};
auto left = checkLargestBST(root->left);
auto right = checkLargestBST(root->right);
// cout<<root->data<<" = ";
// for(int x: left)
// cout<<x<<"L "; cout<<"|| ";
// for(int x: right)
// cout<<x<<"R "; cout<<"|| ";
vector<int> retvec = {INT_MIN, INT_MAX, 0};
//if not a bst tree
if(left[maxval] >= root->data or right[minval] <= root->data)
return retvec;
retvec[size] = 1 + left[size]+right[size];
retvec[minval] = min(left[minval], root->data);
retvec[maxval] = max(right[maxval], root->data);
ans = max(ans, retvec[size]);
// for(int x: retvec)
// cout<<x<<"A ";
// cout<<endl;
return retvec;
}
};
//{ Driver Code Starts.
/* Driver program to test size function*/
int main() {
int t;
scanf("%d ", &t);
while (t--) {
string s, ch;
getline(cin, s);
Node* root = buildTree(s);
Solution ob;
cout << ob.largestBst(root) << endl;
}
return 0;
}
// } Driver Code Ends