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Your SQLite3 library does not support FTS4 #3
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Fixed in the last commit. |
Still have the problem. Python 2.7.10 (default, Feb 7 2017, 00:08:15) IPython 4.2.0 -- An enhanced Interactive Python. In [1]: import sqlite3 In [2]: con = sqlite3.connect('getsploit.db') In [3]: cur = con.cursor() In [4]: for (v, ) in cur.execute('pragma compile_options'): maybe for python 2.7.*, you should change you code like this: It works for me~ |
Wow. |
http://www.sqlite.org/fts3.html yes, for me it's ok |
Got it. |
python script on mac , full text search sqlite database, tips:Your SQLite3 library does not support FTS4., recompile sqlite, command "pragma compile_options" shows ENABLED_ FTS4,but python script still shows not support FTS4. Any solution?
system & program version
macos Sierra develop beta3
python 2.7.13
sqlite3 3.19.3
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