Need help in skipping cronjob when already scripts for previous cronjob are running

[CodeWithSid675]

I have written a cron job as given below

var cron = require('node-cron');
var taskMap = {};
let job = cron.schedule('*/1 * * * * ', ()=>{
var shell = require('./utils/child_helper');

var commandList = [
"node *****",
"node *****",
"node ******"
]

shell.series(commandList , function(err,res){
// console.log('executed many commands in a row');
console.log('done')
});
});

which need to run on every 1 min but the scripts inside the cron may take more than 1 min.
I need to skip the cron for the moment when the scripts are still running .
Can anyone help me on it.

Calling cron from app.js as below code

const express = require('express');
const app = express();
const bodyParser = require('body-parser');
var port = 3000;
require('./cronController').job.start();

app.use(bodyParser.urlencoded({ extended: true }));
app.use(bodyParser.json());
app.listen(port , ()=>{
let dateTime = new Date();
let message = 'Server is running on Port :- ' + port + ' started at :- ' + dateTime;
console.log(message);
});

[wahengchang]

there are two things that I can think about may help:

1- killing child process

• https://stackoverflow.com/questions/53269578/node-js-process-exit-vs-childprocess-kill
• https://solidgeargroup.com/invoking-background-processes-from-nodejs/

const { spawn } = require('child_process');
const grep = spawn('grep', ['ssh']);
grep.on('close', (code, signal) => {
  console.log(
    `child process terminated due to receipt of signal ${signal}`);
});
// Send SIGHUP to process

2- wraping your child process as js (promise)

as I see your commandList are all js script, why dont u execute them by JS function ?

changing this to

var commandList = [
"node script1.js",
"node script2.js",
"node script3.js"
]

var commandList = [fun1, fun2, fun3]
shell.series(commandList , async function(err,res){
 await fun1()
 await fun2()
 await fun3()
});

[CodeWithSid675]

Thank you!