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防止（p+r）的和超过int类型最大值 #269

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calmpeng opened this issue Mar 13, 2019 · 1 comment

calmpeng commented Mar 13, 2019

 // 取p到r之间的中间位置q,防止（p+r）的和超过int类型最大值
    int q = p + (r - p)/2;

这也太牛逼了吧，这都想的到！！

The text was updated successfully, but these errors were encountered:

hjpcs commented Jun 11, 2019

看到二分查找那一节，/2还可以优化成位运算>>1

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