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Create Partition Array According to Given Pivot.java
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class Solution { | ||
public int[] pivotArray(int[] nums, int pivot) { | ||
int[] res = new int[nums.length]; | ||
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int pointer = 0; | ||
for (int i = 0; i < nums.length; i++) { | ||
if (nums[i] < pivot) { | ||
res[pointer++] = nums[i]; | ||
} | ||
} | ||
for (int i = 0; i < nums.length; i++) { | ||
if (nums[i] == pivot) { | ||
res[pointer++] = nums[i]; | ||
} | ||
} | ||
for (int i = 0; i < nums.length; i++) { | ||
if (nums[i] > pivot) { | ||
res[pointer++] = nums[i]; | ||
} | ||
} | ||
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return res; | ||
} | ||
} |