simpler explanation of $RAKULIB

also remove reference to $PERL6LIB.

Author: eiro

doc/Language/5to6-nutshell.pod6

@@ -1533,39 +1533,27 @@ shell injection vulnerabilities with such code.
 
 =head2 Perl module library path
 
-In Perl one of the environment variables to specify extra search paths for
-Perl modules is C<PERL5LIB>.
+Perl use C<PERLLIB> and C<PERL5LIB> to specify extra search paths for modules
+and Both of them are ignored by Raku. Instead, you need to use X<C<RAKULIB>|RAKULIB>.
+The directory separator also changed from ':' to ','.
 
-=for code :lang<shell>
-$ PERL5LIB="/some/module/lib" perl program.pl
-
-In Raku this is similar, one merely needs to change a number!  As you
-probably guessed, you just need to use X<C<PERL6LIB>|PERL6LIB>:
-
-=for code :lang<shell>
-$ PERL6LIB="/some/module/lib" raku program.p6
-
-In Perl one uses the ':' (colon) as a directory separator for C<PERL5LIB>, but
-in Raku one uses the ',' (comma).  For example:
+So the equivalent of
 
 =for code :lang<shell>
 $ export PERL5LIB=/module/dir1:/module/dir2;
 
-but
+is
 
 =for code :lang<shell>
-$ export PERL6LIB=/module/dir1,/module/dir2;
-
-(Raku does not recognize either the C<PERL5LIB> or the older Perl environment
-variable C<PERLLIB>.)
+$ export RAKULIB=/module/dir1,/module/dir2;
 
-As with Perl, if you don't specify C<PERL6LIB>, you need to specify the
+As with Perl, if you don't specify C<RAKULIB>, you need to specify the
 library path within the program via the C<use lib> pragma:
 
 =for code :lang<perl>
 use lib '/some/module/lib'
 
-Note that C<PERL6LIB> is more of a developer convenience in Raku (as
+Note that C<RAKULIB> is more of a developer convenience in Raku (as
 opposed to the equivalent usage of C<PERL5LIB> in Perl) and shouldn't be
 used by module consumers as it could be removed in the future.  This is
 because Raku's module loading isn't directly compatible with operating