Full Stack Engineer
-
de Groen Solutions
- The Netherlands
- https://degroen.solutions
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recursive, descendants
recursive, descendants 1let nodeCurrent: AnchorNode = this;
2let idxChild = 0;
3for (; ;) {
4result.push(nodeCurrent);
5while (nodeCurrent !== this && idxChild >= nodeCurrent.children.length) {
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