Support for combining characters

[benjamingeer]

The way I usually type an accented character (on macOS with the British keyboard) is that I first type the accent, then the character it will combine with. For example, to get ü, I type Alt-U to get the umlaut, then 'u'.

If I do this in the editor demo, something strange happens. Starting with an empty editor window, I type the umlaut, and this appears:

Then when I type the 'u':

[argimenes]

Hi Benjamin, I have finished my other changes to SPEEDy and am ready to start integrating your scripts. But I just wanted to check with you whether your script will work with single characters at a time, or whether it has to be given an entire text to make the decisions it makes. I ask, because SPEEDy works on the basis that a single character maps to a single HTMLSpanElement, and the only way I can think of integrating your script would be to intercept the key-press event and pass the keyboard character to the script. This means that I would need to call your library one character at a time. Is this possible? Thanks, Iian

…

On Wed, 20 Feb 2019 at 22:58, Benjamin Geer ***@***.***> wrote: The way I usually type an accented character (on macOS with the British keyboard) is that I first type the accent, then the character it will combine with. For example, to get ü, I type Alt-U to get the umlaut, then 'u'. If I do this in the editor demo, something strange happens. Starting with an empty editor window, I type the umlaut, and this appears: [image: screenshot 2019-02-20 at 13 52 17] <https://user-images.githubusercontent.com/558389/53093106-cc9e7480-3516-11e9-922e-c81dcce17795.png> Then when I type the 'u': [image: screenshot 2019-02-20 at 13 56 29] <https://user-images.githubusercontent.com/558389/53093312-5c442300-3517-11e9-8caf-6873047bfac7.png> — You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHub <#19>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AAj4oRLpE4-zHUzAt7o22ZccRXpIrGGPks5vPUZngaJpZM4bFJ__> .

[benjamingeer]

Hi Iian,

Thanks for letting me know, that's great. I'll reply in #18.

Ben