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Change the executable name in the README examples to bootstrap (#476)
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bmoffatt committed Dec 23, 2022
1 parent c80f8ac commit 99a9a4b
Showing 1 changed file with 7 additions and 6 deletions.
13 changes: 7 additions & 6 deletions README.md
Original file line number Diff line number Diff line change
Expand Up @@ -48,8 +48,9 @@ Preparing a binary to deploy to AWS Lambda requires that it is compiled for Linu
## For developers on Linux and macOS
``` shell
# Remember to build your handler executable for Linux!
GOOS=linux GOARCH=amd64 go build -o main main.go
zip main.zip main
# When using the `provided.al2` runtime, the handler executable should be named `bootstrap`
GOOS=linux GOARCH=amd64 go build -o bootstrap main.go
zip lambda-handler.zip bootstrap
```

## For developers on Windows
Expand All @@ -68,17 +69,17 @@ in cmd.exe:
set GOOS=linux
set GOARCH=amd64
set CGO_ENABLED=0
go build -o main main.go
%USERPROFILE%\Go\bin\build-lambda-zip.exe -o main.zip main
go build -o bootstrap main.go
%USERPROFILE%\Go\bin\build-lambda-zip.exe -o lambda-handler.zip bootstrap
```

in Powershell:
``` posh
$env:GOOS = "linux"
$env:GOARCH = "amd64"
$env:CGO_ENABLED = "0"
go build -o main main.go
~\Go\Bin\build-lambda-zip.exe -o main.zip main
go build -o bootstrap main.go
~\Go\Bin\build-lambda-zip.exe -o lambda-handler.zip bootstrap
```
# Deploying your functions

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