Picks a file from same-name filenames with different extensions based on preference around esm or cjs
Say you have a two files, one named file.js and one named file.mjs in a project. You need to choose
one of them for reasons, which one you choose depends on context and preference. Context here being,
what is the type field on package.json - if anything. Preference being, for each possible type
field ('module', 'commonjs', undefined) which extensions take priority over others.
import pyckle from 'pyckle'const pyckle = require('pyckle')The directory to select files from.
The file name, without extension.
Default:
{
module: ['m', 'j', 'c'],
commonjs: ['j', 'c', 'm'],
undefined: ['m', 'j', 'c']
}An object with three keys specified for each package.json scenario - "type":"module", "type":"commonjs" or no type. Each holds an array, with three elements, 'm' representing the .mjs extension, 'j' representing the .js extension, and 'c' representing the .cjs extension.
The lower the index of a character, the high the priority applied to files with the extension it represents.
Result is the same Result object as supplied by the is-file-esm module, see https://github.com/davidmarkclements/is-file-esm#api
MIT