实现C语言结构体与 JSON 快速相互转换。 依赖cJSON库,未对cJSON进行任何更改。
git clone --recursive https://github.com/fisherboys/struct2json.git
- mkdir build && cd build
- cmake ..
- make
/* 结构体数据 */
typedef struct s2j_case1 {
int8_t num1;
int32_t num2;
double num3;
} s2j_case1_t;
/* Step1. 描述结构体数据 */
static const obj_type_info_t s2j_case1_stuct_subtypes[] = {
{
/* int8_t num1成员的类型为OBJ_TYPE_INT8 */
.obj_type = OBJ_TYPE_INT8,
/* obj_name为json字符串中对应的key */
.obj_name = "Int8",
/* int8_t num1相对结构体起始点的地址偏移 */
.obj_addr = rela_addr(s2j_case1_t, num1),
},
{
.obj_type = OBJ_TYPE_INT32,
.obj_name = "Int32",
.obj_addr = rela_addr(s2j_case1_t, num2),
},
{
.obj_type = OBJ_TYPE_DOUBLE,
.obj_name = "Double",
.obj_addr = rela_addr(s2j_case1_t, num3),
},
OBJ_TYPE_STRUCT_END
};
const obj_type_info_t s2j_case1_struct_type = {
.obj_type = OBJ_TYPE_STRUCT,
.obj_name = NULL,
.obj_size = sizeof(s2j_case1_t),
.obj_addr = NULL,
.child = s2j_case1_stuct_subtypes,
};
/**
* 本例的json字符串
* {
* "Int8": 1,
* "Int32": 2,
* "Double": 3.3
* }
*/
void example_case_struct_with_number(void) {
s2j_case1_t data = { 0 };
s2j_case1_t result = { 0 };
char *json_str = NULL;
/* Step2. 初始化 */
s2j_init(&s2j_case1_struct_type, &data);
s2j_init(&s2j_case1_struct_type, &result);
data.num1 = 1;
data.num2 = 2;
data.num3 = 3.3;
/* Step3. 序列化或反序列化 */
json_str = s2j_serialize(&s2j_case1_struct_type, &data);
if (NULL == json_str) {
printf("Case1 serialize failed\n");
return;
}
printf("Serialized data:\n%s\n", json_str);
if (0 != s2j_deserialize(json_str, &s2j_case1_struct_type, &result)) {
printf("Case1 deserialize failed\n");
goto failure;
}
printf("Deserialized result:\nnum1[%d], num2[%d], num3[%lf]\n", result.num1, result.num2, result.num3);
failure:
/* Step4. 释放资源 */
s2j_fini(&s2j_case1_struct_type, &data);
s2j_fini(&s2j_case1_struct_type, &result);
free(json_str);
}