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van Kampen #26
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In the examples given in that section, they were all sets. On Mon, Mar 25, 2013 at 4:30 PM, Daniel R. Grayson <notifications@github.com
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No, in the final example, only A was a set. (A=1). Beginning a subsection with "however" is too abrupt, in any case. |
I've tried to smooth it out somewhat; still thinking about the best way to explain the general issue. |
We read this:
When$A$ , $B$ , and $C$ are not all sets, however, the version of the van Kampen theorem proven in the previous section is not as useful, since it does not identify the path-space of $P$ with a set presented in terms of \emph{set-level data}.
But I'm confused, because up to now A, B, and C have been types, not sets.
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