Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

van Kampen #26

Closed
DanGrayson opened this issue Mar 25, 2013 · 3 comments
Closed

van Kampen #26

DanGrayson opened this issue Mar 25, 2013 · 3 comments

Comments

@DanGrayson
Copy link
Member

We read this:

When $A$, $B$, and $C$ are not all sets, however, the version of the van Kampen theorem proven in the previous section is not as useful, since it does not identify the path-space of $P$ with a set presented in terms of \emph{set-level data}.

But I'm confused, because up to now A, B, and C have been types, not sets.

@mikeshulman
Copy link
Contributor

In the examples given in that section, they were all sets.

On Mon, Mar 25, 2013 at 4:30 PM, Daniel R. Grayson <notifications@github.com

wrote:

We read this:

When $A$, $B$, and $C$ are not all sets, however, the version of the van
Kampen theorem proven in the previous section is not as useful, since it
does not identify the path-space of $P$ with a set presented in terms of
\emph{set-level data}.

But I'm confused, because up to now A, B, and C have been types, not sets.


Reply to this email directly or view it on GitHubhttps://github.com//issues/26
.

@DanGrayson
Copy link
Member Author

No, in the final example, only A was a set. (A=1). Beginning a subsection with "however" is too abrupt, in any case.

@mikeshulman
Copy link
Contributor

I've tried to smooth it out somewhat; still thinking about the best way to explain the general issue.

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

No branches or pull requests

2 participants