Lab 1 done #10
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Lab 1 done #10
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avtohem
commented
Dec 6, 2019
Exercises/1-seq.js
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| const seq = (...f) => a => (!isNaN(a) ? | ||
| f.reduce((v, fn) => fn(v), a) : | ||
| seq(a, ...f)); |
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Потом подсмотрел это решение у romchik38 .... оно соответсвует формулировке задачи )))
Но это все равно далеко от минимальной длины...
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reduce не нужен, нужна рекурсия
tshemsedinov
reviewed
Dec 7, 2019
Exercises/1-seq.js
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| const seq = (...f) => a => (!isNaN(a) ? | ||
| f.reduce((v, fn) => fn(v), a) : | ||
| seq(a, ...f)); |
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reduce не нужен, нужна рекурсия
Exercises/1-seq.js
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| @@ -1,5 +1,7 @@ | |||
| 'use strict'; | |||
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| const seq = f => g => x => 0; | |||
| const seq = (...f) => a => (!isNaN(a) ? | |||
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Зачем isNaN, нужно проверять typeof, функция ли?
tshemsedinov
reviewed
Dec 9, 2019
Exercises/1-seq.js
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| @@ -1,5 +1,7 @@ | |||
| 'use strict'; | |||
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| const seq = f => g => x => 0; | |||
| const seq = f => g => x => ((typeof x === 'number') ? | |||
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Suggested change
| const seq = f => g => x => ((typeof x === 'number') ? | |
| const seq = f => g => x => (typeof x === 'number' ? |
tshemsedinov
approved these changes
Dec 10, 2019
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👍 |
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Не знаю как даже приблизится к минимально установленной длине ((((