Python Problem

[Antim-IWP]

3169. Count Days Without Meetings

_Please give me the Solution for this.

You are given a positive integer days representing the total number of days an employee is available for work (starting from day 1). You are also given a 2D array meetings of size n where, meetings[i] = [start_i, end_i] represents the starting and ending days of meeting i (inclusive).

Return the count of days when the employee is available for work but no meetings are scheduled.

[iamAntimPal]

class Solution:
    def countDays(self, days: int, meetings: List[List[int]]) -> int:
        meetings.sort()
        ans = last = 0
        for st, ed in meetings:
            if last < st:
                ans += st - last - 1
            last = max(last, ed)
        ans += days - last
        return ans

This is the solution and join this orgnization