Extend arrays with a remove functionality.

[MaxTymchii]

Hi there,

As I can see wrench does not support such an important action as removing some items from an array as hash-table for example.
I tried to set null for the corresponding item but null is 0 so it's not what I want as a result.

Now, I create a new array without this item by copying all the elements, but it's definitely how it should work :)

[jingoro2112]

This already exists, the "._remove" function: I consider this a failure of the documentation :( apologies for not making it more clear. *compiler-intrinsics* Some compiler directives are included for working with arrays and hash tables: hashTable = { 1:"one", 2:"two", 3:3, "str":6 }; // ._count print( hashTable._count ); // prints 4 // ._exists hashTable._exists( 2 ); // returns 'true' hashTable._exists( 20 ); // returns 'false // ._remove hashTable._exists( 2 ); // returns 'true' hashTable._remove( 2 ); hashTable._exists( 2 ); // now false

…

On Sat, Jun 8, 2024 at 4:11 AM Max ***@***.***> wrote: Hi there, As I can see wrench does not support such an important action as removing some items from an array as hash-table for example. I tried to set null for the corresponding item but null is 0 so it's not what I want as a result. Now, I create a new array without this item by copying all the elements, but it's definitely how it should work :) — Reply to this email directly, view it on GitHub <#26>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AALIKA6MZ4CIWSTYU7QNBELZGK4ETAVCNFSM6AAAAABI7ZKAKWVHI2DSMVQWIX3LMV43ERDJONRXK43TNFXW4OZWG44TGOJRGY> . You are receiving this because you are subscribed to this thread.Message ID: ***@***.***>

[MaxTymchii]

I know about a hash table and it works for me. I am talking now about an array. after tiny test I have also a question for hash table actually too.

var hashTable = {:};
hashTable["mock"] = "value";
hashTable["mock2"] = "value2";
hashTable["mock3"] = "value3";

var array = {1, 2, 3, 4, 5};


hashTable._remove("mock");
array._remove(2);


println( "hashTable" );
for ( var v, var k : hashTable ) {
    print(v);
    println(k);
}

println( "array" );
for ( var v : array ) {
    println(v);
}

Result:

hashTable
00
0value3
0value2
array
1
2
3
4
5

As you can see 2 value on array is available. Hashtable shows really interesting behavior.

P.S.: I think I can try to help you with examples on your website if you want.

Regards,
Max.

[jingoro2112]

OH ... removing from arrays? well.. so you mean turning: [ 0, 1, 2, 3 ] into [ 0, 2, 3 ] by removing element 1? I could have sworn I added that.. yeah oops.. it's part of the container lib that I stubbed out and never finished!! array::count() array::remove( array, where [,count] ) array::insert( array, where [,count] ) hash::exists( hash, key ) hash::remove( hash, key ) Guess it's time for me to finish it :P I'll make it part of my next update, I'm halfway through the parser re-work, so declarations like this will work: var a = { 1, 2, { 3.1, 3.2, 3.3 }, { 4:"four"} }; nested container declaration :) If I'm lucky I'll have it done and unit-tested within a day or so!

…

-Curt

On Sat, Jun 8, 2024 at 12:59 PM Max ***@***.***> wrote: I know about a hash table and it works for me. I am talking now about an array. after tiny test I have also a question for hash table actually too. var hashTable = {:}; hashTable["mock"] = "value"; hashTable["mock2"] = "value2"; hashTable["mock3"] = "value3"; var array = {1, 2, 3, 4, 5}; hashTable._remove("mock"); array._remove(2); println( "hashTable" ); for ( var v, var k : hashTable ) { print(v); println(k); } println( "array" ); for ( var v : array ) { println(v); } Result: hashTable 00 0value3 0value2 array 1 2 3 4 5 As you can see 2 value on array is available. Hashtable shows really interesting behavior. P.S.: I think I can try to help you with examples on your website if you want. Regards, Max. — Reply to this email directly, view it on GitHub <#26 (reply in thread)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AALIKA3LWIGCG34NRCMYSS3ZGMZ7JAVCNFSM6AAAAABI7ZKAKWVHI2DSMVQWIX3LMV43SRDJONRXK43TNFXW4Q3PNVWWK3TUHM4TOMJVGI4DQ> . You are receiving this because you commented.Message ID: ***@***.***>

[MaxTymchii]

Please, also check my print logs of a hashtable, as you can see it's an extraordinary thing with keys after removing one of them that has an almost identical name!

[jingoro2112]

it would appear foreach key and value is broken! I will fix this immediately and put in unit tests, also the array remove is not working either.. :(

…

On Sat, Jun 8, 2024 at 1:32 PM Curt Hartung ***@***.***> wrote: OH ... removing from arrays? well.. so you mean turning: [ 0, 1, 2, 3 ] into [ 0, 2, 3 ] by removing element 1? I could have sworn I added that.. yeah oops.. it's part of the container lib that I stubbed out and never finished!! array::count() array::remove( array, where [,count] ) array::insert( array, where [,count] ) hash::exists( hash, key ) hash::remove( hash, key ) Guess it's time for me to finish it :P I'll make it part of my next update, I'm halfway through the parser re-work, so declarations like this will work: var a = { 1, 2, { 3.1, 3.2, 3.3 }, { 4:"four"} }; nested container declaration :) If I'm lucky I'll have it done and unit-tested within a day or so! -Curt On Sat, Jun 8, 2024 at 12:59 PM Max ***@***.***> wrote: > I know about a hash table and it works for me. I am talking now about an > array. after tiny test I have also a question for hash table actually too. > > var hashTable = {:}; > hashTable["mock"] = "value"; > hashTable["mock2"] = "value2"; > hashTable["mock3"] = "value3"; > > var array = {1, 2, 3, 4, 5}; > > > hashTable._remove("mock"); > array._remove(2); > > > println( "hashTable" ); > for ( var v, var k : hashTable ) { > print(v); > println(k); > } > > println( "array" ); > for ( var v : array ) { > println(v); > } > > > Result: > > hashTable > 00 > 0value3 > 0value2 > array > 1 > 2 > 3 > 4 > 5 > > As you can see 2 value on array is available. Hashtable shows really > interesting behavior. > > P.S.: I think I can try to help you with examples on your website if you > want. > > Regards, > Max. > > — > Reply to this email directly, view it on GitHub > <#26 (reply in thread)>, > or unsubscribe > <https://github.com/notifications/unsubscribe-auth/AALIKA3LWIGCG34NRCMYSS3ZGMZ7JAVCNFSM6AAAAABI7ZKAKWVHI2DSMVQWIX3LMV43SRDJONRXK43TNFXW4Q3PNVWWK3TUHM4TOMJVGI4DQ> > . > You are receiving this because you commented.Message ID: > ***@***.***> >

[jingoro2112]

Okay should be fixed in the latest 5.0.1 push: var hashTable = {:}; hashTable["mock"] = "value"; hashTable["mock2"] = "value2"; hashTable["mock3"] = "value3"; var array = {1, 2, 3, 4, 5}; hashTable._remove("mock"); array._remove(2); println( "hashTable" ); for ( var v, var k : hashTable ) { print(v); println(k); } println( "array" ); for ( var v : array ) { println(v); } Result: hashTable mock3value3 mock2value2 array 1 2 4 5

…

On Sat, Jun 8, 2024 at 4:56 PM Curt Hartung ***@***.***> wrote: it would appear foreach key and value is broken! I will fix this immediately and put in unit tests, also the array remove is not working either.. :( On Sat, Jun 8, 2024 at 1:32 PM Curt Hartung ***@***.***> wrote: > OH ... removing from arrays? well.. so you mean turning: > [ 0, 1, 2, 3 ] > into > [ 0, 2, 3 ] > by removing element 1? > > I could have sworn I added that.. yeah oops.. > > it's part of the container lib that I stubbed out and never finished!! > > array::count() > array::remove( array, where [,count] ) > array::insert( array, where [,count] ) > hash::exists( hash, key ) > hash::remove( hash, key ) > > Guess it's time for me to finish it :P I'll make it part of my next > update, I'm halfway through the parser re-work, so declarations like this > will work: > > var a = { 1, 2, { 3.1, 3.2, 3.3 }, { 4:"four"} }; > > nested container declaration :) > > If I'm lucky I'll have it done and unit-tested within a day or so! > > -Curt > > > On Sat, Jun 8, 2024 at 12:59 PM Max ***@***.***> wrote: > >> I know about a hash table and it works for me. I am talking now about an >> array. after tiny test I have also a question for hash table actually too. >> >> var hashTable = {:}; >> hashTable["mock"] = "value"; >> hashTable["mock2"] = "value2"; >> hashTable["mock3"] = "value3"; >> >> var array = {1, 2, 3, 4, 5}; >> >> >> hashTable._remove("mock"); >> array._remove(2); >> >> >> println( "hashTable" ); >> for ( var v, var k : hashTable ) { >> print(v); >> println(k); >> } >> >> println( "array" ); >> for ( var v : array ) { >> println(v); >> } >> >> >> Result: >> >> hashTable >> 00 >> 0value3 >> 0value2 >> array >> 1 >> 2 >> 3 >> 4 >> 5 >> >> As you can see 2 value on array is available. Hashtable shows really >> interesting behavior. >> >> P.S.: I think I can try to help you with examples on your website if you >> want. >> >> Regards, >> Max. >> >> — >> Reply to this email directly, view it on GitHub >> <#26 (reply in thread)>, >> or unsubscribe >> <https://github.com/notifications/unsubscribe-auth/AALIKA3LWIGCG34NRCMYSS3ZGMZ7JAVCNFSM6AAAAABI7ZKAKWVHI2DSMVQWIX3LMV43SRDJONRXK43TNFXW4Q3PNVWWK3TUHM4TOMJVGI4DQ> >> . >> You are receiving this because you commented.Message ID: >> ***@***.***> >> >

[ander-theo]

Note to update an error in the documentation, in section foreach:

for( var k,v : somArray )
{
   // same as above but k will take on the value 0, 1 and 2
}

(https://home.workshopfriends.com/wrench/www/#:~:text=for(%20var%20k%2Cv%20%3A%20somArray%20)%0A%7B%0A%20%20%20//%20same%20as%20above%20but%20k%20will%20take%20on%20the%20value%200%2C%201%20and%202%0A%7D)

I was struggling with this failing until I saw what you wrote above:
for ( var v, var k : hashTable ) {
print(v);
println(k);
}

[MaxTymchii]

Big-big thanks to you. Now everything works perfectly!

[jingoro2112]

thank you!

…

On Wed, Oct 9, 2024 at 7:01 PM Ander ***@***.***> wrote: Note to update an error in the documentation, in section foreach: for( var k,v : somArray ) { // same as above but k will take on the value 0, 1 and 2 } ( https://home.workshopfriends.com/wrench/www/#:~:text=for(%20var%20k%2Cv%20%3A%20somArray%20)%0A%7B%0A%20%20%20//%20same%20as%20above%20but%20k%20will%20take%20on%20the%20value%200%2C%201%20and%202%0A%7D ) I was struggling with this failing until I saw what you wrote above: for ( var v, *var* k : hashTable ) { print(v); println(k); } — Reply to this email directly, view it on GitHub <#26 (reply in thread)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AALIKAZX2KFASGRVWTIL7DDZ2WYU5AVCNFSM6AAAAABI7ZKAKWVHI2DSMVQWIX3LMV43URDJONRXK43TNFXW4Q3PNVWWK3TUHMYTAOBZG44DANA> . You are receiving this because you commented.Message ID: ***@***.***>