Linux fzf on i686 PC possible? I can successfully build it but it won't work.

[richardlovas]

Hi!

I know that this is a long shot since by looking at the binary releases I came to the conclusion that the i686 platform is unsupported, but I thought it's worth a question here.

I run Gentoo Linux on a secondary PC which is really old -- i686 architecture, AMD Athlon-XP processor with MMX and SSE but no SSE2 --, but I like to tinker with it. I managed to cross compile the latest Go compiler for it, so I could build fzf, and I also succeeded with that -- no errors in the build process, everything honky dory at a first glance.

However, when I try to use fzf in any way -- simply by running fzf, or Ctrl-r, or Alt-c, etc. -- it quits on me with the following error:

unknown option:

Just this, without anything after the colons. I also couldn't find any logs or anything where I could find further info about the nature of the error. I'm guessing that either the lack of x86_64 or the lack of SSE2 will be the culprit (though SSE2 is the least suspect here because this isn't a SIGILL error that I expect in those cases).

I'm open to suggestions about either how to troubleshoot this issue, or to just live without fzf on this old PC 😆 It's not critical for me or anything, so I just thought that I'll drop this question here before I unmerge the package and consider this to be impossible 😉

[richardlovas]

Nevermind, the problem went away, and both my git source built one and the one I just installed with my package manager works flawlessly. Sorry for the unnecessary topic, closing it now.