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isDisjoint
Subhajit Sahu edited this page Dec 2, 2022
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17 revisions
Check if sets have no value in common.
Similar: union, intersection, difference, symmetricDifference, isDisjoint.
function isDisjoint(x, y)
// x: a set
// y: another set
const set = require('extra-set');
var x = new Set([1, 2, 3]);
var y = new Set([3, 4]);
set.isDisjoint(x, y);
// → false
var y = new Set([4]);
set.isDisjoint(x, y);
// → true