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pelevesque committed Jun 29, 2019
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2 changes: 2 additions & 0 deletions .gitignore
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node_modules
coverage
14 changes: 14 additions & 0 deletions .travis.yml
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language: node_js

node_js:
- stable
- 7.5.0

install:
- npm install

script:
- npm run cover

# send coverage data to Coveralls
after_script: "cat coverage/lcov.info | node_modules/coveralls/bin/coveralls.js"
21 changes: 21 additions & 0 deletions LICENSE.txt
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MIT License

Copyright (c) 2019 Pierre-Emmanuel Lévesque

Permission is hereby granted, free of charge, to any person obtaining a copy
of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
copies of the Software, and to permit persons to whom the Software is
furnished to do so, subject to the following conditions:

The above copyright notice and this permission notice shall be included in all
copies or substantial portions of the Software.

THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
SOFTWARE.
129 changes: 129 additions & 0 deletions README.md
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[![Build Status](https://travis-ci.org/pelevesque/has_required_substrings_at_sums.svg?branch=master)](https://travis-ci.org/pelevesque/has_required_substrings_at_sums)
[![Coverage Status](https://coveralls.io/repos/github/pelevesque/has_required_substrings_at_sums/badge.svg?branch=master)](https://coveralls.io/github/pelevesque/has_required_substrings_at_sums?branch=master)
[![JavaScript Style Guide](https://img.shields.io/badge/code_style-standard-brightgreen.svg)](https://standardjs.com)

# has_required_substrings_at_sums

Checks if a string has required substrings after given sums.

## Node Repository

https://www.npmjs.com/package/@pelevesque/has_required_substrings_at_sums

## Installation

`npm install @pelevesque/has_required_substrings_at_sums`

## Tests

### Standard Style & Unit Tests

`npm test`

### Unit Tests & Coverage

`npm run cover`

## Usage

### Parameters

```js
str (required)
requiredSubstrings (required)
options (optional) default = { substringsToDigits = null, sumPlainDigits = true, allowSubstringBleeding = false }
```

### Requiring

```js
const hasRequiredSubstringsAtSums = require('@pelevesque/has_required_substrings_at_sums')
```

### Basic Usage

@see https://github.com/pelevesque/sum-digits to understand how the sum is calculated.

`requiredSubstrings` is an object of sum -> substring pairs. `true` is returned
if all substrings are found directly following their associated sums.

```js
const str = '123a45'
const requiredSubstrings = { 1: 'a' }
const result = hasRequiredSubstringsAtSums(str, requiredSubstrings)
// result === false
```

```js
const str = '123a45'
const requiredSubstrings = { 6: 'a' }
const result = hasRequiredSubstringsAtSums(str, requiredSubstrings)
// result === true
```

```js
const str = '123man45dinosaur'
const requiredSubstrings = { 6: 'man', 15: 'dinosaur' }
const result = hasRequiredSubstringsAtSums(str, requiredSubstrings)
// result === true
```

```js
// the substring must come directly after the sum (here b is directly after the sum, not a)
const str = '123ba45'
const requiredSubstrings = { 6: 'a' }
const result = hasRequiredSubstringsAtSums(str, requiredSubstrings)
// result === false
```

### SubstringsToDigits

You can use the `substringsToDigits` object to give numeric values to substrings
so that they are counted during summing.

```js
const str = '123!$$$a'
const requiredSubstrings = { 15: 'a' }
const substringsToDigits = { '!': 4, '$$$': 5 }
const result = hasRequiredSubstringsAtSums(str, requiredSubstrings, {
substringsToDigits: substringsToDigits
})
// result === true
```

### SumPlainDigits Flag

You can set the `sumPlainDigits` flag to false if you only want to sum
`substringsToDigits`.

In the following example, `1`, `2`, and `3` are not summed.

```js
const str = '123!a'
const requiredSubstrings = { 4: 'a' }
const substringsToDigits = { '!': 4 }
const sumPlainDigits = false
const result = hasRequiredSubstringsAtSums(str, requiredSubstrings, {
substringsToDigits: substringsToDigits,
sumPlainDigits: sumPlainDigits
})
// result === true
```

### AllowSubstringBleeding Flag

The `allowSubstringBleeding` flag is `false` by default. It it used when you want
to allow the last required substring to be incomplete if the string is too short.
In the following example, the last substring `canal` starts after the right sum,
but remains incomplete since the string ends. Normally this would return `false`.
With `allowSubstringBleeding` set to `true`, it returns `true`.

```js
const str = '123can'
const requiredSubstrings = { 6: 'canal' }
const allowSubstringBleeding = true
const result = hasRequiredSubstringsAtSums(str, requiredSubstrings, {
allowSubstringBleeding: allowSubstringBleeding
})
// result === true
```
39 changes: 39 additions & 0 deletions index.js
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'use strict'

const sumDigits = require('@pelevesque/sum-digits')

const isObjectEmpty = (obj) =>
Object.entries(obj).length === 0 && obj.constructor === Object

module.exports = (str, requiredSubstrings,
{
substringsToDigits = null,
sumPlainDigits = true,
allowSubstringBleeding = false
} = {}
) => {
if (isObjectEmpty(requiredSubstrings)) return true
if (!isObjectEmpty(requiredSubstrings) && str === '') return false
for (let i = 0, len = str.length; i < len; i++) {
const sum = sumDigits(str.substr(0, i + 1), {
substringsToDigits: substringsToDigits,
sumPlainDigits: sumPlainDigits
})
if (requiredSubstrings.hasOwnProperty(sum)) {
let substring = requiredSubstrings[sum]
if (allowSubstringBleeding) {
const substringMaxLength = str.length - i - 1
if (substring.length > substringMaxLength) {
substring = substring.substr(0, substringMaxLength)
}
}
const target = str.substr(i + 1, substring.length)
if (substring.localeCompare(target) !== 0) {
break
} else {
delete requiredSubstrings[sum]
}
}
}
return isObjectEmpty(requiredSubstrings)
}
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