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Fix typos; MasterDuke++
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zoffixznet committed May 6, 2017
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8 changes: 4 additions & 4 deletions doc/Language/glossary.pod6
Original file line number Diff line number Diff line change
Expand Up @@ -758,7 +758,7 @@ In English language, L<reify means|http://www.dictionary.com/browse/reify> to
similar, in that conceptual things, like "elements of an infinite list" get
I<reified> when you try to operate on some of them:
# A list containing innfinite number of unreified Fibonacci numbers:
# A list containing infinite number of unreified Fibonacci numbers:
my @fibonacci = 1, 1, * + * … ∞;
# We reify 10 of them, looking up the first 10 of them with array index:
Expand Down Expand Up @@ -812,12 +812,12 @@ already-reified elements from the L<Seq>'s cache.
Note that above we assigned the C<gather> to a L<Scalar> container (the C<$>
sigil), not the L<Positional> one (the C<@> sigil). The reason is that the
C<@>-sigiled variables are I<mostly lazy>. What this means is their
C<@>-sigiled variables are I<mostly lazy>. What this means is they
I<reify the stuff assigned to them> right away I<most of the time>. The only
time they don't do it is when the items are known to be
L«C<is-lazy>|/routine/is-lazy», like our sequence generated with infinity as the
end point. We we to assign the C<gather> to a C<@>-variable, the C<say> statements
inside of it would've been printed right away.
end point. Were we to assign the C<gather> to a C<@>-variable, the C<say>
statements inside of it would've been printed right away.
Another way to fully-riefy a list, is by calling L«C<.elems>|/routine/elems» on
it. This is the reason why checking whether a list contains any items is best
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2 changes: 1 addition & 1 deletion doc/Language/traps.pod6
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Expand Up @@ -22,7 +22,7 @@ language.
=head2 Constants are Compile Time
Constants are computed at compile time, so if use them in modules keep in mind
Constants are computed at compile time, so if you use them in modules keep in mind
their values will be frozen due to pre-compilation:
# WRONG (most likely):
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