Update cookbook/01strings/01-00introduction.pl

The code:
<code>my $string = "1" ~ "1" + 10;</code>
will actually output "111" in Perl6.

Since in Perl5, "~" (actually ".") is the same precedence as "+",
but in Perl6, numeric operations have higher precedence.
So the "1" + 1 part will be evaluated first, giving "111" as the result.

Just a small modification here. :)

Author: Abcxyzp

cookbook/01strings/01-00introduction.pl

@@ -164,7 +164,7 @@ =head1 Strings as numbers
 Context sensitivity is the essence of Perl.  Keeping this in mind, what
 would you expect to be the output string, for the following?
 
-    my $string = "1" ~ "1" + 10; # 12 or 21?
+    my $string = "1" ~ "1" + 10; # 12, 21, or even... "111"?
     say $string;
 
 But, "1+1", surrounded by quotation marks, either '' or "", stringifies
@@ -185,7 +185,7 @@ =head1 Strings as numbers
 
 =end pod
 
-my $string = "1" ~ "1" + 10; # 12 or 21?
+my $string = "1" ~ "1" + 10; # 12, 21, or even... "111"?
 say $string;
 say "1 + 1"; # literally: 1 + 1
 say eval "1 + 1";    # 2