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sage: V = span([[1/7,0,0] ,[0,1,0]], ZZ); V Free module of degree 3 and rank 2 over Integer Ring Echelon basis matrix: [1/7 0 0] [ 0 1 0] sage: T = matrix(ZZ,3,[1,0,0,0,0,0,0,0,0]); T [1 0 0] [0 0 0] [0 0 0] sage: W = T.kernel_on(V); W.basis() [ (0, 1, 0) ] sage: W.is_submodule(V) False
This is surprising, isn't it? (Patch comes up in a minute, but I need to create the ticket first.)
Component: linear algebra
Author: Georg S. Weber
Reviewer: William Stein
Merged: sage-4.5.2.alpha0
Issue created by migration from https://trac.sagemath.org/ticket/9425
The text was updated successfully, but these errors were encountered:
Attachment: trac_9425_kernel_on.patch.gz
created against the older Sage-4.4.2, but that shouldn't matter
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Looks good to me. Thanks!
jasongrout
williamstein
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This is surprising, isn't it? (Patch comes up in a minute, but I need to create the ticket first.)
Component: linear algebra
Author: Georg S. Weber
Reviewer: William Stein
Merged: sage-4.5.2.alpha0
Issue created by migration from https://trac.sagemath.org/ticket/9425
The text was updated successfully, but these errors were encountered: